a gun of mass 10000 kg fires a shot of mass 50 kg with a velocity of 250 m/s. find the velocity of recoil of gun
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Explanation:
ANSWER
From the momentum conservation, we have
Initial momentum = final momentum.
Therefore, if V is the velocity of gun just after firing then
0=50V+0.5×200
V=−2m/s (-ve sign indicates direction of gun is opposite to that of bullet)
Now, since the final velocity of gun is zero,
0−(−2)
2
=2a×1
a=−2m/s
2
(-ve sign indicates deceleration)
Therefore frictional force is equal to force with which gun is moving backward
F=2×50=100N
plz folllow me
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