Question

a gun of mass 100kg fires a shell of mass 2kg with a velocity of 200m/s calculate the recil velocity of gun
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Answer 1

according to linear momentum conservation

m1v1=m2v2

let the velocity of gun be v

100×v=2×100

v=2m/s

the recil velocity of gun=2m/s

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Answer 2

Answer:mass1=100kg

mass2=2kg

initial velocity=0

"""""""""""""''of shell=o

final velocity of gun=200m/s

""""""”"""'''''''''of shell = to find

m1u1+m2u2=m1v1+m2v2

100×0+2×0=100×200+2×v2

0=20000+2v2

-20000=2v2

-10000=v2

Explanation: