Question

a gun of mass 10kg fires a bullet of 50g with a velocity 300m with what velocity does the gun recoil​

Answer 1

Answer:

Using momentum concentration,

mg vg + mb ub =0

10* uy = 50/1000 * 500

=vg = 2.5m/s

Explanation:

May this math help you

Answer 2

Answer:

here,

mass of gun (mg)=10kg

mass of bullet(mb)=50gm=50*10^(-3)kg

velocity of bullet(vb) =300m/s

velovity of recoil(vg)=?

we have

from conservation of momentum

0=mb*vb+mg*vg

0=50*10^(-3)*300+10*vg

vg=-15/10 m/s

    =-1.5m/s