Question

a gun of mass 15 kg fires a bullet of mass 150 g with a velocity of 1000 m/s calculate the velocity of a recoil of a gun​

Answer 1

Given:

• Mass of gun, M₁ = 15 kg
• Mass of bullet, M₂ = 150 g = 0.15 kg
• Initial velocity of recoil of a gun, u₁ = 0 m/s
• Initial velocity of bullet, u₂ = 0 m/s
• Final velocity of bullet, v₂ = 1000 m/s

To find:

• Velocity of recoil of a gun.

Solution:

Let v₁ be the velocity of gun.

Applying momentum conversion principle,

✰ M₁u₁ + M₂u₂ = M₁v₁ + M₂v₂

Putting the values,

• 15 × 0 + 0.15 × 0 = 15 × v₁ + 0.15 × 1000
• 15 × 0 + 0.15 × 0 = 15 × v₁ + 150
• 0 + 0.15 × 0 = 15 × v₁ + 150
• 0 + 0 = 15 × v₁ + 150
• 0 = 15 × v₁ + 150
• 0/15 = v₁ + 150
• v₁ = - 150/15
• v₁ = - 10 m/s

∴ The velocity of a recoil of a gun = 10 m/s

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Answer 2

Answer:

$\huge\sf{❃Answer:-}$

10m/s