Question

A GUN OF MASS 2kg FIRES A BULLET OF MASS 20g MOVING WITH A SPEED OF 25 m/s, what is the gun's recoil velocity?

Answer 1

Answer:

-0.25m/s

Explanation:

Let 1 denote gun and 2 denote bullet.

m1= 2kg

m2=20g=0.02kg

Let v denote final velocity and u the initial velocity.

u1=0

v1=x

u2=0

u2=25m/s

Now, according to law of conservation of linear momentum, we know

m1u1+m2u2=m1v1+m2v2

Putting values:

2*0+ 0.02*0= 2*x+ 0.02* 25

0= 2x+ 0.5

x=-0.5/2= -0.25m/s.

Thus, gun' s recoil velocity is -0.25m/s

HOPE THIS HELPS:)