Question

A gun of mass 3 kg fires a bullet of 30 kg. the bullet acquires
a velocity of 100 m/sec. Calculate the velocity
with which the gun recoil​

Answer 1

Answer:

the recoil velocity of the gun =1 m/s

Explanation:

Given that,

A gun of mass 3 kg fires a bullet of 30 g

and bullet fired at the speed of 100 m/s

here we have,

Mass of gun = 3 kg

mass of bullet = 30 g

= 0.03 kg

now,

let the recoil velocity of the gun be v

now we know that,

by the law of conservation of momentum

Momentum is conserved

so,

momentum of bullet = momentum of gun

momentum = mass × velocity

momentum of gun = mass of gun × it's recoil velocity

and momentum of bullet = it's mass × it's velocity

now,

momentum of gun = momentum of bullet

putting the values,

3 × v = 0.03 × 100

3v = 3

v = 3/3

v = 1 m/s

so,

the recoil velocity of the gun

will 1 m/s