Question

A gun of mass 3 kg fires a bullet of 30g. The bullet takes 0.03 seconds to love through the barrel of the Gun and accuses the Velocity of our 100m/s . Calculate:

1 Velocity of the gun when recoils
2 The force experienced on the gun man

Answer 1

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✴The Mass of the Gun(m1) = 3 kg

✴The Mass of the bullet(m2) = 30g = 0.03kg

✴The Velocity of Gun (v1) = ?

✴The Velocity of Bullet (v2) = 100m/s


✔According to the $\textbf{Conservation\:of\\Linear\:Momentum:}$

=》M1 V1 = M2 V2
=》3 × V1 = 0.03kg × 100m/s
=》V1 = $\frac{0.03 \times 100}{3}$

=》V1 = $\frac{3}{3}$


=》V1 = 1 m/s $\boxed{ans}$

Force Exerted on the GUN Man :-

=》F = MA
=》F = 3 × $\frac{v - u}{t}$

=》F = 3 × $\frac{1 - 0}{0.03}$

=》F = 1000 N $\boxed{ans}$



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Hope this helps. . . . . . ❤❤