a gun of mass 3 kg fires a bullet of mass 30 g the bullet takes 0.0 03 s to move through the barrel of the gun and acquires a velocity of mass 100 m/s calculate the velocity with which the gun recoil the force exerted on gunman due to recoil of the gun
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Mass of gun m1 = 30g = 0.03 kg
Mass of bullet m2 = 3 kg
Velocity of bullet v1 = 100m/s
V2 = ?
m1v1=m2v2
0.03×100=3×v2
v2=1.1m/s
acceleration of bullet = v-u/t
110-0/0.03
= 3666.6 m/s
f=ma
0.03×3666.6 = 109.9N
Mass of gun m1 = 30g = 0.03 kg
Mass of bullet m2 = 3 kg
Velocity of bullet v1 = 100m/s
V2 = ?
m1v1=m2v2
0.03×100=3×v2
v2=1.1m/s
acceleration of bullet = v-u/t
110-0/0.03
= 3666.6 m/s
f=ma
0.03×3666.6 = 109.9N
Arpit245:
it is wrong
yes it is wrong
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