a gun of mass 3 kg fires a bullets of mass 30g the bullets take 0.0035 s to move through the barrel of the gun and acquires a velocity of 100 m/s. Calculate (1) The velocity with gun recoil.
(2) The force exerted of gun man
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For gun m1=3kg v1=?
For bullet m2=30g=0.03kg v2=110m/s
By law of conservation of momentum
M1*v1=m2*v2
3*v1=0.03*110
V1=0.03*110/3
V1=1.1m/s
Aof bullet=v-u/t
110-0/0.03=3666.6m/s^2
F=ma=0.03*3666.6=109.9N
This may help you..___
For bullet m2=30g=0.03kg v2=110m/s
By law of conservation of momentum
M1*v1=m2*v2
3*v1=0.03*110
V1=0.03*110/3
V1=1.1m/s
Aof bullet=v-u/t
110-0/0.03=3666.6m/s^2
F=ma=0.03*3666.6=109.9N
This may help you..___
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