Question

.A gun of mass 30 Kg fires a bullet of mass 30 g with a muzzle velocity 300 m/s.
Find the recoil velocity of gun?

Answer 1

Answer:

-39m/s

Explanation:

Mass of gun m2=30kg

Mass of bullet m1=30kg=3/100g

velocity of bullet v1=300m/s

recoil velocity V2=?

total momentum of system before firing=0kgm/s

According to law of conservation of momentum

Total momentum before firing=Total momentum after firing

m1u1+m2u2=m1v1+m2v2

0kgm/s=3/100*300+30*V2

0kgm/s=39*V2

0-39=V2

-39m/s=v2