Question

a gun of mass 3kg fires a bullet of mass 30g.the bullet takes 0.003 sec to move through the barrel of the gun ang acquires a velocity of 110m/s.calculate

the velocity with the gun recoils.

the force exerted on gunman due to recoil..??

Answer 1

calculate the velocity with the gun recoils.

For gun m­1=3kg v1=?

For bullet m2=30g=0.03kg v2=110m/s

By law of conservation of momentum

M1*v1=m2*v2

3*v1=0.03*110

V1=0.03*110/3

V1=1.1m/s





the force exerted on gunman due to recoil.



Aof bullet=v-u/t

110-0/0.03=3666.6m/s2

F=ma=0.03*3666.6=109.9N