Question

A gun of mass 4 kg fires a bullet of 10 g with a velocity of 100 m/s in the forward
direction. Find the recoil velocity of the gun.

Answer 1

Explanation: m1u1+m2u2=m1v1+m2v2

since both are at rest initially

0= 4×v1+0.01×100

0= 4v1+1

-1=4v1

∴ v1= -1/4 = -0.25 m/s

here I have taken bullets velocity +ve