Question

A gun of mass 4kg fires a bullet of log with al
speed of 100m/s in the forward direction, find :
1. The total initial momentum.
2. The recoil velocity of gun.​

Answer 1

Explanation:

Mass of gun, M = 4 kg

Mass of bullet, m = 10 g = 0.01 kg

Speed of bullet, u = 100 m/s

(i)

Initial momentum of the system = 0 kg m/s

Final Momentum of bullet = m × u = 1 kg m/s

(ii)

Let the recoil velocity of the revolver be ‘v’

Mv + mu = 0

=> 4v + 1 = 0

=> v = -0.25 m/s

The negative sign implies the revolver recoils in the direction opposite to that of the bullet.

Answer 2

Answer:

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Explanation:

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