Question

a gun of mass 5 kg fires a bullet of mass 20g with a speed of 100m/s. find the recoil velocity of the gun​

Answer 1

Mark my answer as Brainlist

Answer 2

Step-by-step explanation:

Mass of bullet,

$m = 20g = \frac{20}{1000} = \frac{2}{100} = \frac{1}{50}$

$= \frac{1}{50kg}$

Velocity of bullets,

$v = 100 \frac{m}{ {s}^{2} }$

Mass of gun,

$m = 5kg$

Let recoil velocity of gun =V

Before firing, the system (gun+bullet) is at rest, therefore, initial momentum of the system =0

Final momentum of the system = momentum of bullet + momentum of gun

MV+mv

$\frac{1}{50} \times 100 + 5v \\ = 2 + 5v$

Applying law of conservation of momentum, Final momentum = Initial momentum

i.e,..is..

$2 + 5v = 0 \\ 5v = - 2 \\ v = \frac{ - 2}{5}$

$= - 0.4 \frac{m}{ {s}^{2} }$

Negative sign shows that the direction of recoil velocity of the gun is opposite to the direction of the velocity of the bullet.

hope it's helpful