a gun of mass 5 kg fires a bullet of mass 50g with a velocity of 100 m/s calculate the velocity of the gun
Answers
ANSWER
From the momentum conservation, we have
Initial momentum = final momentum.
Therefore, if V is the velocity of gun just after firing then
0=50V+0.5×200
V=−2m/s (-ve sign indicates direction of gun is opposite to that of bullet)
Now, since the final velocity of gun is zero,
0−(−2)
2
=2a×1
a=−2m/s
2
(-ve sign indicates deceleration)
Therefore frictional force is equal to force with which gun is moving backward
F=2×50=100NWhat would you like to ask?
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Work, Energy and Power
Collisions in Two Dimensions
A gun of mass 50 kg fir...
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Asked on December 30, 2019 by
Shaurya Maheshwary
A gun of mass 50 kg fires a bullet of mass 0.5 kg with velocity of 200ms
−1
. If the gun moves through 1 m back before coming to rest, the frictional force on the gun is:
MEDIUM
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ANSWER
From the momentum conservation, we have
Initial momentum = final momentum.
Therefore, if V is the velocity of gun just after firing then
0=50V+0.5×200
V=−2m/s (-ve sign indicates direction of gun is opposite to that of bullet)
Now, since the final velocity of gun is zero,
0−(−2)
2
=2a×1
a=−2m/s
2
(-ve sign indicates deceleration)
Therefore frictional force is equal to force with which gun is moving backward
F=2×50=100N