Question

a gun of mass 5kg fires 10g bullet at the rate of 20 bullets per second with the speed of 400 m/s . what is the force required to hold the gun in position ?

Answer 1

Here,Mass Of Machine Gun(m)= 5kg

Mass of each Bullet, (M)=35g=0.005kg

Velocity Of Bullet(v)=400m/s

No.Of Bullets/sec=400/60=20/3

Force required = rate of change of linear momentum of bullets=n(mv)/t

=20/3×(0.005×400)/1=13.34N

Answer 2

mass of the gun equal to 5 kg
mass of the bullet is 10 gram
speed of bullet equal to 400 m per second.
therefore force required to keep the gun in a position=change in momentum of bullets/time taken.