Question

a gun release A bullet of mass 50 grams with velocity of 200 metre per second and get embedded into a person of mass 80 kgs after that they move together with common velocity V1 and T1 then find V1​ plzz give answer fast

Answer 1

Answer:1.17m/s

Explanation:

Applying conservation of momentam as no external forces are acting

M1V1 +M2V2 =(M1+M2)*V

(50/1000)*200 +0 =(0.5+80)*V

V=1.17m/s