Question

A gun weighting 10 kg fires A bullet of mass 0.03 kg with a velocity of 300ms-1 with what velocity does the gun recoil please full solved answer​

Answer 1

Given ,

Mass of Gun (M) = 10 kg

Mass of bullet (m) = 0.03 kg

Velocity of bullet (v) = 300 m/s

We know that ,

The recoil velocity of gun is given by

$\boxed{ \sf{Recoil \: velocity \: (V) = - \frac{mv}{M} }}$

Thus ,

V = -(0.03 × 300)/10

V = -0.03 × 30

V = -0.9 m/s

[ The negative sign of V indicates it is opposite to the velocity of bullet ]

Therefore ,

• The recoil velocity of gun is 0.9 m/s

Answer 2

Answer:

Momentum of the bullet equals the momentum of the gun.

Momentum equals to :

Mass × Velocity

We substitute into the formulae and get :

0.03 × 330 = 10 × V

9.9 = 10V

V = 0.99 m/s

Momentum before firing is zero since both the gun and the bullet are at rest and their velocities are zero.

Momentum after firing is equal to momentum of the gun plus the momentum of the bullet which are equal and opposite.

This is therefore :

330 × 0.03 × 2 = 19.8Kgm/s