Question

A gun with a mass of 4.00kg shoots a 0.70kg bullet with an acceleration of 6.00m/s2 North.

A. What is the force on the gun?

B. What is the magnitude and direction of acceleration of the gun?

Answer 1

Answer:

Given,

Mass(gun) = 4.00kg

Mass(bullet) = 0.70kg

acceleration on bullet = 6m/s²

A) by conversation of momentum:

P of gun = P of bullet

M(g)×v(g) = M(b)×v(b)

differentiate w.r.t. time

{since mass is constant }

Then we get

M(g)×a(g) = M(b)×a(b). {dv/dt = a}

since F = M(g)×a(g)

F(g) = M(b)×a(g)

F(g) = 0.7×6

F(g) = 4.2

in opposite direction of bullet