a guy attached sa wire 24m long to a vertical pole of height 18m and has a stake attached to the other end. how far from the base of the pole should the stake be driven so that the wire will be taught.
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draw a right angled triangle ABC such that
<B =90
Length=AC=24cm
height=BC=18cm
distance between foot of the pole to end of the wire= AB
using Phythagoras theorem
AB^2+BC^2=AC^2
AB^2= AC^2-BC^2
= (24)^2-(18)^2
=(24+18)(24-18)
=42*6
=7*(6*6)
AB = 6*root7cm
<B =90
Length=AC=24cm
height=BC=18cm
distance between foot of the pole to end of the wire= AB
using Phythagoras theorem
AB^2+BC^2=AC^2
AB^2= AC^2-BC^2
= (24)^2-(18)^2
=(24+18)(24-18)
=42*6
=7*(6*6)
AB = 6*root7cm
nakulmaheshwari:
thanks
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48
Answered by
11
hey mate this is ur answer.....
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