A guy wire attached to a vertical pole of height 18 m is 24 m long and has a stake attached to the other end. How far from the base of the pole should the stake be driven so that the wire will be taut?
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A guy wire attached to a vertical pole of height 18 m is 24 m long.
We have to find : How far from the base of pole should the stake be driven so that the wire will be taut.
Here,
Let, AB be the height of vertical pole.
AC be a wire.
In ΔABC, By using pythagoras theorem we get, :-
( Hypotenuse )² = ( Height )² + ( Base )²
AC² = AB² + CB²AC²=AB²+CB²
\sf \pink {24² = 18² + CB²}24²=18²+CB²
\tt \red {576 = 324 + CB^{2} }576=324+CB
2
\bf \red {576 - 324 = CB²}576−324=CB²
\rm \green {252 = CB²}252=CB²
\mathcal\red {6√7m = CB}6√7m=CB
HENCE, THE STAKE MAY BE PLACED AT A DISTANCE CB = 6√7m, FROM THE BASE OF THE POLE
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