Question

. A gymnast dismounts the uneven parallel bars. Her height, h(feet), depends on the time, t(sec), that she is in the air as follows.h = - 16 t2+ 8t + 8.

Where will she be after 1 second?

Answer 1

Answer:

h = -16t^2 + 8t + 8

h(1) = -16(1)^2 + 8(1) + 8

=-16+8+8 = 0

She'll no longer be in the air after 1 second. She'll hit the ground, or mat or whatever's on the floor

maximum height reached is reached at h'=-32t+8 = 0 when t=1/4 second

she starts at 8 feet high, goes up to max height = -16(1/4)^2 + 8(1/4)+ 8 = -1+2+8 = 9 feet high

then goes down for 3/4 of a second until she's at 0 feet high

-16t^2 is the deceleration effect of gravity: -32ft per sec per sec

8t = velocity, 8 ft per second = initial velocity

8 ft = initial height

hope you are satisfied with the answer

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