a(h,6),b(2,3) c(-6,k) are the co ordinates of vertices of a triangle whose centroid is A(1,5).FIND H AND K
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Given, A ≡ (h, -6) , B ≡(2,3) and C (-6, k) also centroid of given triangle ABC is G ≡(1,5) .
We know, if vertices of triangle are (x₁ , y₁) , (x₂, y₂) and (x₃, y₃)
Then, centroid of triangle is given by {(x₁ + x₂ + x₃)/3 , (y₁ + y₂ + y₃)/3 }
so, G ≡ (1, 5) ≡ { (h + 2 - 6)/3 , (-6 + 3 + k)/3 }
(h + 2 - 4)/3 = 1 ⇒ (h - 4)/3 = 1
⇒ h = 7
5 = (-6 + 3 + k)/3 ⇒ 5 = (-3 + k)/3
⇒15 = -3 + k
⇒k = 18
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