A hag contains red, white balls. There are total 10 balls. If a ball is select a
2)
mandom, then probability of red ball is 2/5.
Total numbers of red balls are ()4 Total numbers of white balls are
(6) 6
(c) 5
(d) 3
(a) 4 (b) 5 3) If a white ball is select at random then probability is
(0) 6 (d) 10
2/5. (b) 3/5. (c) 4/5. (d) 0
(a)
4) If a white or a red ball is select at random then probability is
(b) 0 (c) 2/5 (d) None of the above
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Answered by
5
Answer:
Answer
P (of red ball) =1−(
10
3
+
5
2
)
=1−(3+
10
4
)
=1−
10
7
=
10
10−7
P (of red ball) =
10
3
No. of black balls =
totalno.ofballs
20
5
2
=
totalno.ofballs
20
⇒50 = total no. of balls
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