a hailstone of temparature 0 degree celsius is dropped from a height of 1 km from an insulating surface,so that all of its is kinetic energy is converted into heat, then how much part of it will be melted by the heart
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Answered by
4
Answer:
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Hailstone possesses potential energy due to is height. Let k be the fraction ice that melts.
Hence,
Potential energy=k×latent heat
mgh=kmL⇒k=
L
gh
=
330×10
3
10×1000
≈
33
1
Answered by
1
Answer:
The height from which the Hailstone falls is 1 km.
The energy lost by the hailstone is the potential energy and as it falls, this energy converts into heat energy. This heat energy is utilized in melting the hailstone.
So, the part of the hailstone melted is given by equating the potential energy to the latent heat of fusion.
mgh=KmL
∵ Latent heat of ice =3.36×10
5
J/kg
⇒K=
L
gh
=
3.36×10
5
10×1000
=
33
1
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