A hairdryer is rated to operate at 240 V and 2.5 A. How long must the hairdryer be in use for it to transfer 1 kJ of energy?
Answers
Answered by
1
Answer:
5/3sec
Explanation:
H=IVt
H=1000J
IV=240×2.5=600
10/6=t
5/3=t
no E/IV
Energy released in current circuit is termed as heat loss so E=H
oh, okay. thanks
kindly follow me for more solution
Similar questions
Explanation:
First, calculate the power that the hairdryer operates at:
P = IV = 2.5 × 240 = 600 W
Rearrange P=Et
P
=
E
t
and convert energy to Joules, so 1 kJ = 1000 J:
t=Ep
t
=
E
p
= 1000600
1000
600
= 1.67 s
or use and rearrange E = IVt, so t = EIV