Question

A half metre rule is pivoted at the centre with two weights of 20 gf and 12 gf suspended

at a perpendicular distance of 6cm and 10cm from the pivot respectively as shown below.

50 cm

20gf 12gf

6 cm 10 cm

i. Which of the two forces acting on the rigid rod causes clockwise moment?

ii. Is the rod in equilibrium?

iii. The direction of 20gf force is reversed. What is the magnitude of the resultant moment of

the forces on the rod? [2018]​

Answer 1

Answer:

refer to the attachment

Answer 2

1. The force F2=12 gf causes clockwise moment and force F1=20 gf causes anticlockwise moment
2. For an object to remain in equilibrium, two conditions must be satisfied - both the net force and the net torque must be equal to zero. An example of an object in equilibrium is a rod that is free to rotate about a hinge at one end
3. half metre rod is pivoted at the centre with two weights of 20 gf and 12 gf suspended at a perpendicular distance of 6 cm and 10 cm from the ...
4. Top answer