Question

A half wave rectifier is fed from a supply of 230 V, 50 Hz with step down transformer of ratio 3:1.
Resistive load connected is 10 KΩ. The diode forward 10KΩ. The diode forward resistance is 75Ω and transformer secondary is 10Ω.
Calculate the DC load current, DC load voltage, efficiency and ripple factor.​

Answer 1

Answer:

You have the system reversed. The transformer would come first and then the rectifier, since the transformer can’t work on DC. With a turns ratio of 8:1 the voltage on the secondary would be 240/8 = 30 volts.

The peak voltage of a sine wave is the RMS (root mean squared voltage) x square root of 2. That would be 42.5 volts. A typical silicon diode drops about 0.7 volts so the peak voltage would be about 42 volts.

Explanation:

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