A half-wave rectifier, the peak value of the ac voltage across the secondary of the transformer is
20√2 V. If no filter circuit is used, the maximum de voltage across the load will be::
a. 28.28 V
b. 14.14 V
c. 20 V
d. 9V
Basic Electronics Engineering
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Answer:
b) 14.14 Volt
Explanation:
Vrms =Vm√2
Vrms =20 √2= 20 V√2
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