A hall 25 m long and 20m wide is surrounded by verandah of uniform width of 4m. Find:
a. The area of the verandah
B. The cost of flooring it at rupee 15 per square metre.
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As there is a uniform width of 4 m the length and breadth of the hall increases by 8m. Therefore the area of verandah would be=
33×28-(25×20)
924-500
424 sq m.
The cost of flooring it would be 424×15=Rs. 6360
33×28-(25×20)
924-500
424 sq m.
The cost of flooring it would be 424×15=Rs. 6360
Answered by
1
Answer:
the length is 25 m and wide is 20 m
ao then solve
l×b =25×20=500
the verandha of uniform of 4 m
so length is increase 8m and wide is 8m
then (25+8)×(20+8)
33×28=924
the area of verandha is 924-500=424
the cost of floaring at rupee 15 per square
424×15=rupees 6360 ans..
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