Question

a Hall effect set up, sample of n-type Ge has a donor density of 10 raise to 21 /m3 . Find the Hall voltage developed if the magnetic field used is 0.6 T, current density J is 500 A/m2and width of the sample is 5 mm​

Answer 1

Answer:

donor density of 10 raise to 21 /m3 . Find the Hall voltage developed if the magnetic field used is 0.6 T, current density J is 500 A/m2and width of the sample is 5 mm

Answer 2

Answer:

The Hall voltage developed is about 0.186 mV.

Explanation:

From the above question,

The magnitude of the Hall voltage can be calculated the usage of the following formula:

                      V_H = (IB)/ne

where V_H is the Hall voltage, I is the contemporary density, B is the magnetic discipline strength, n is the cost service density, and e is the basic charge.

Given:

Donor density n = $10^{21$ /$m^3$

Magnetic discipline power B = 0.6 T

Current density J = five hundred A/$m^2$

Width of the pattern w = 5 mm

                                     = 0.005 m

First, we want to calculate the cost provider density, because the pattern is n-type Ge, we comprehend that every donor impurity atom contributes one free electron to the conduction band. Thus, we have:

          n = donor density

             = 1$0^{21$ /$m^3$

Next, we can calculate the Hall voltage the usage of the system above:

          V_H = (IB)/ne

                   = (0.0055000.6)/(10^21 * 1.602 × $10^{-19$)

          V_H = 0.186 mV (rounded to three widespread figures)

Therefore,

          The Hall voltage developed is about 0.186 mV.

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