A hall has 4 windows, each 4 m wide and high,2 doors each 2.5 m tall and 1m wide.If a hall is 20m long, 18m wide, and 6m high, find the cost of painting it's wall at 38 per m²
prabin100:
nice question
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Answered by
0
Answer:
CSA of cuboid - 4 x area of windows - 2 x area doors x cost = 14706 Rs.
Answered by
2
Answer: Rs 14706
Step-by-step explanation:
L = 20 m
B = 18 m
H = 6 m
Surface area = lateral surface area of hall - area of doors + Windows
= 2(L + b ) H - [4(4 × 4) + 2(2.5 × 1)]
= 12(38) - [64 + 5]
= 456 - 69
= 387 m^2
Now m^2 = rs 38
Cost of painting the hall = 387 × 38
= rs 14706
Hope it helps
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