A hall is 12 meter 5 decimetre braod and 14 meter 5 decimetre long it is to be paved with tiles 15 centimetres square.what will it cost if the price of one dozen tiles is Rs 4.80
Answers
Answer:
Step-by-step explanation:
The cost of tiles required to pave the hall is Rs. 48,333.20.
• Given,
Breadth of the hall = 12 m 5 dm
Length of the hall = 14 m 5 dm
• For calculations, the units must be made equal. So, we will convert 'm' into 'dm'
Now, 1 m = 10 dm
∴ For breadth, 12 m 5 dm = 12 × 10 dm + 5 dm
= 120 dm + 5 dm
= 125 dm
• For length,
14 m 5 dm = 14 × 10 dm + 5 dm
= 140 dm + 5m
= 145 dm
• Now, area of the hall = length × breadth
=> Area of the hall = 145 dm × 125 dm
= 18125 dm²
• Given,
Area of each tile with which the hall is to be paved = 15 cm²
• Now,
Number of tiles required to pave the hall = Area of the hall / Area of one tile
• Again, the units of the area of the hall and the area of the tiles are different. Therefore, we shall convert dm² into cm².
• We know that, 1 dm = 10 cm
=> (1 dm)² = (10 cm)²
=> 1 dm² = 100 cm²
∴ The area of the hall in cm² is 18,125 × 100 cm² = 18,125,00 cm²
• Now, number of tiles required to pave the hall = 18,125,00 cm² / 15 cm²= 1,20,833.33 1,20,833
• Cost of 1 dozen of tiles is given as Rs. 4.80.
1 dozen of tiles means 12 tiles.
=> Cost of 12 tiles = Rs. 4.80
• By unitary method,
Cost of 1 tile = Rs. 4.80 / 12 = Rs. 0.40
=> Cost of 1,20,833 tiles = Rs. 0.40 × 1,20,833 = Rs. 48,333.20 (Answer)