Question

A hall is 16 meters long 14 meters broad and 10 meter high. Each wall has a door 5 m. long and 4m. wide and a window of 3m. long and 2m. wide. Find the area of four wall of the room.sorry for that question:)​

Answer 1

Answer:

Length of hall = 16m

Wide of hall = 14m

Height of hall = 10m

Step-by-step explanation:

Answer 2

Answer:

Given :-

A hall is 16 meters long, 14 meters broad and 10 meter high.

Each wall has a door 5 meters long and 4 meters wide and a window of 3 meters long and 2 meters wide.

To Find :-

What is the area of four wall of the room.

Area of the rooms except wall and window.

Solution :-

First, we have to find the area of four wall of the room :

Given :

Length of hall = 16 m

Breadth of hall = 14 m

Height = 10 m

As we know that,

♣ Area of four walls of the room of cuboid :

$\begin{gathered}\begin{gathered}\longmapsto \sf\boxed{\bold{\pink{Area =\: 2h(l + b)}}}\\\end{gathered} \end{gathered}$

where,

h = Height

l = Length

b = Breadth

According to the question by using the formula we get,

⇢ Area of four walls of the rooms :

$\implies \sf 2 \times 10(16 + 14)$

$\implies \sf 20(30)$

$\implies \sf 20 \times 30$

$\implies \sf\bold{\red{600\: {m}^{2}}}$

Hence, the area of four walls of the room is 600 m² .

∴ The area of four walls of the room is 600 m².

Again, we have to find the area four windows :

As we know that,

♣ Area of four windows :

$\begin{gathered}\begin{gathered}\longmapsto \sf\boxed{\bold{\pink{Area\: =\: 4(l \times b)}}}\\\end{gathered} \end{gathered}$

Given :

Length = 3 m

Breadth = 2 m

According to the question by using the formula we get,

⇢ Area of four windows :

$\implies \sf 4(3 \times 2)$

$\implies \sf 4(6)$

$\implies \sf 4 \times6$

$\implies \sf\bold{\green{ 24\: {m}^{2}}}$

Hence, the area of four windows is 24 m².

Now, we have to find the area of four doors :

♣ Area of four doors :

$</p><p>\begin{gathered}\begin{gathered}\longmapsto \sf\boxed{\bold{\pink{Area =\: 4(l \times b)}}}\\\end{gathered} \end{gathered}$

Given :

Length = 5 m

Breadth = 4 m

According to the question by using the formula we get,

⇢ Area of four doors :

$\implies \sf 4(5 \times 4)$

$\implies \sf 4(20)$

$\implies \sf 4 \times 20$

$\implies \sf\bold{\green{80\: {m}^{2}}}$

Atlast, we have to find the area of the rooms except wall and window :

★ Area of the rooms except wall and window = Area of four walls - Area of four doors + Area of four windows

Given :

Area of four walls = 600 m²

Area of four doors = 80 m²

Area of four windows = 24 m²

According to the question by using the formula we get,

⇢ Area of the rooms except wall and window :

$\implies \sf 600\: m^2 - 80\: m^2 + 24\: m^2$

$\implies \sf 600\: m^2 - 104\: m^2$

$\implies \sf\bold{\red{496\: m^2}}$

∴ The area of the rooms except wall and window is 496 m².