Question

A hall is 16 meters long 14 meters broad and 10 meter high. Each wall has a door 5 m. long and 4m. wide and a window of 3m. long and 2m. wide. Find the area of four wall of the room.​

Answer 1

Answer:

5 m. If the height of the room is 15 m,then find the cost of painting its four walls at rupees 6.20 per square meter.

Step-by-step explanation:

Answer 2

Answer:

496m^2

Step-by-step explanation:

the area of rectangle is lb

lateral surface area of cuboid = lh + bh + lh + bh= 2h(l + b)= 2*10(16 + 14)=600m^2

now we have to subtract the area of door and window

area of 4 door = 4(lb)= 4*5*4=80m^2

area of 4 window = 4(lb)= 4*3*2=24m^2

not that here 4 is multiplied because there are 4 walls and each wall has 4 doos and 4 windows

total area of wall= (lateral surface area) -( area of door + area of window)

                           =600-(80 + 24)=496m^2