Question

A hall is 16 meters long 14 meters broad and 10 meter high. Each wall has a door 5 m. long and 4m. wide and a window of 3m. long and 2m. wide. Find the area of four wall of the room.

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Answer 1

Answer:

The answer is 496 m².

Explanation:

Its a rectangular hall. so we have to find the area of 2 types of walls.

2×(Area of 1st type of wall) + 2×(Area of 2nd type of wall) = Total area.

1st type = (16×10) - ((4×5)+(2×3)) = 134

2nd type = (14×10) - ((4×5)+(2×3)) = 114

Total area = 2×134 + 2×114 = 496 m².

Hope it helps. Thank you.

Mark as brainliest if it was helpful.

Answer 2

$\Large{\bf{\orange{{{\underline{\underline{\underline{Given:-}}}}}}}}$

• $\mathfrak{Length \: of \: hall = \: 16 m }$
• $\mathfrak{Breadth \: of \: hall = \: 14 m }$
• $\mathfrak{ Height \: of \: hall \: = \: 10 m}$
• $\mathfrak{Length \: of \: door \: = \: 5 m }$
• $\mathfrak{Breadth \: of \: door \: = \: 4m }$
• $\mathfrak{Length \: of \: window \: = \: 3m }$
• $\mathfrak{Breadth \: of \: window \: = \: 2m }$

$\Large{\bf{\orange{{{\underline{\underline{\underline{To \: find:-}}}}}}}}$

• $\mathfrak{Area \: of \: four \: walls \: of \: room}$

$\Large{\bf{\orange{{{\underline{\underline{\underline{Formula \: used:-}}}}}}}}$

• $\boxed{2(l + b) \times h}$

where,

• l = length
• B = Breadth
• H = height

$\Large{\bf{\orange{{{\underline{\underline{\underline{Step \: by \: step \: explaination:-}}}}}}}}$

Using the given formula we are calculating the area of four walls...

⟹ 2 (l + b)*h

⟹ 2 (16 + 14) × 10

⟹ 60 × 10

⟹ 600 m²

Using the given formula we are calculating the area of four windows...

⟹ 4 ( l × b )

⟹ 4 (3×2)

⟹ 24 m²

Using the given formula we are calculating the area of four doors...

⟹ 4 ( l × b)

⟹ 4 (5 × 4)

⟹ 4 × 20

⟹ 80 m²

Now calculating the area of four walls without door and windows...

⟹ 600 - (80 + 24)

⟹ 600 - 104

⟹ 496 m²

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