Question

a hall is 25m long and 18m wide. a path 1.5m wide is constructed around it. calculate the cost of cementing it at the rate ₹20.50 per square metre

Answer 1

hola^_^

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length of path=25+1.5=26.5 m

breadth of path=18+1.5= 19.5 m


area of path= 26.5×19.5

=516.75 m

cost=516.75×20.50

=
10, 593.375 rs..


hope it helps^_^

be brainly

Answer 2

Given :

a hall is 25m long and 18m wide. a path 1.5m wide is constructed around it.

To Find :

calculate the cost of cementing it at the rate ₹20.50 per square metre

Solution:

Length of hall = 25 m

Breadth of hall = 18 m

We are give that a path 1.5m wide is constructed around it.

So,Outer length = 25+1.5+1.5=25+3=28 m

Outer breadth = 18+1.5+1.5=21 m

Area of path = Outer area - Inner area = $(28 \times 21)-(25 \times 18)=138 sq.m.$

Cost of cementing 1 sq.m. = Rs.20.5

Cost of cementing 138 sq.m. = $20.5 \times 138 =Rs.2829$

Hence The cost of cementing the path is Rs.2829