A hall is 37.5 m long and 11.2 m wide. Its floor is
to be covered with rectangular tiles of size 15 cm by
7 cm. Find the total cost of tiling the hall at the rate
of 1.25 per tile.
A. 25700
B. 50000
C. 45000
D. 48500
Answers
Floor in rectangular figure
area
=length × breadth
= 9.68 m × 6.2 m
= 60.016 square meter
area of one tile
=l × b
= 22cm × 10cm
=220 square centimeter
= 220/100 meter
=2.2m
total tiles require
=60.016/2.2
=27.28
TOTAL cost
=27.28×2.50
=68.2 rupees
AnswEr :
◑ Dimensions of Hall :
- Length ( L ) = 37.5 m = 3750 cm
- Breadth ( B ) = 11.2 m = 1120 cm
◑ Dimensions of Tile :
- Length ( l ) = 15 cm
- Breadth ( b ) = 7 cm
• We will calculate No. of Tiles Now :
⇒ No. of Tiles × Area of Tile = Area of Hall
⇒ No. of Tiles × ( l × b ) = ( L × B )
⇒ No. of Tiles × ( 15 × 7 ) = ( 3750 × 1120 )
⇒ No. of Tiles × 105 cm² = 42,00,000 cm²
⇒ No. of Tiles = 42,00,000 cm² /105 cm²
⇒ No. of Tiles = 40,000
_________________________________
• We will Calculate Cost of Tiling Now :
⇝ Cost = No. of Tiles × Rate
⇝ Cost = 40,000 × Rs 1.25
⇝ Cost = 40,000 × 125 /100
⇝ Cost = 400 × 125
⇝ Cost = Rs. 50,000
∴ Total Cost of Tiling is [ B.] Rs. 50,000