Math, asked by vanshchaudhary819, 1 month ago

A hall of dimensions 30m×10m was to be painted. On the first day, one-fifth of the area was painted, and half of the remaining was painted on the next day. How much area is left to be painted to complete the task?​

Answers

Answered by rksinha722
9

Answer:

120m^2

Step-by-step explanation:

Area = 30×10 m^2 =300 m^2

on 1st day the area painted =1/5 × 300 m^2 = 60m^2

on 2nd day the area painted = 1/2 of the remaining area = 1/2 ×(300-60) =1/2×240 = 120m^2

therefore, remaining area left to be painted to complete the task = 120m^2

Answered by harshpurbey1980
7

Answer:

120 m2

Step-by-step explanation:

  • Area =30×10m=300m
  • Hall painted on 1st day=1/5×300=60m
  • Hall painted on 2nd Day=1/2×remaining=1/2×300-60=240m2=1/2×240=120m2
  • Area is left to painted=(240-120)=120m2

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