Question

A hall of length 20m, breadth 10m and height 7m is to be painted along walls. How

many cans of paint are required to paint the walls if from each can 30m2

of area is

painted? What will be the cost of painting if cost of each can is Rs. 75?​

Answer 1

Answer:

5

Step-by-step explanation:

Area to be painted = area of the walls + area of ceiling

=2(hl+hb)+lb

=[2×(7×15+7×10)+(15×10)]=500 sq m

No. of cans required =

100

500

=5

Hence, 5 cans are required to paint the walls and the ceiling of the cuboidal hall.

Answer 2

Step-by-step explanation:

2(l+b)h =2(30)×7=420m²

now required paint =420/30 = 14

so 14 cans are required

now cost = 75×14 = ₹1050