Question

a hallow hemispherical bowl of thickness 1 cm has an inner radius of 6cm.Find the radius of metal required to make the bowl​

Answer 1

Answer:

=4421(343-216)=4421×127=558821cm2

Answer 2

Answer:

Inner radius, r = 6 cm

Thickness, t = 1 cm

Outer radius, R = 6+1 = 7 cm

Therefore,

Volume of steel required =

3

2

πR

3

−

3

2

πr

3

=

3

2

×

7

22

×7

3

−

3

2

×

7

22

×6

3

=

21

5588

cm

3