Question

A hallow metal pipe is 63cm long .the inner diameter of cross section is 4cm and the outer diameter is 4.8cm find the total surface area of the pipe​

Answer 1

Answer:

Let the outer surface area be 2πrh

2*22/7*2.4*63

=950.4cm^2

Area of the upper base and lower base is

2*π(R^2-r^2)

2*22/7*(5.74-4)

=10.93cm^2

And,inner surface area is

2πrh

2*22/7*2*63

=792cm^2

Therefore total area equals to (792+10.93+950.4)cm^2

=1753.33cm^2

Thank you