Question

A hammer exerts a force of 1.5 N on each of the two
nails A and B. The area of cross section of tip of nail
A is 2 mm² while that of nail B is 6 mm². Calculate
pressure on each nail in pascal.​

Answer 1

Answer:

on A,

force = 1.5 N

area = 2 mm^2

1 mm = 1/1000 m = 0.001m

1 mm^2 = 1 mm*1mm = 0.001 m * 0.001 m = 0.000001 m^2 = 10^-6 m^2

P = 1.5N/ (2*10^-6) m^2 = 7.5*10^5 Pa

on B,

P = 1.5N/(6*10^-6) m^2 = 2.5*10^5 Pa

PLS MARK AS BRAINLIEST ANSWER

Explanation:

Answer 2

$\bold{For \: nail \: A,}$

$\bold{force \: = \: 1.5N} \\ \bold{area \: = \: 2m {m}^{2} \: to \: {m}^{2} } \\ \bold{1m{m}^{2} \: = \: 1mm \: \times 1mm} \\ \bold{ \: \: \: = 0.001m \times 0.001m} \\ \bold{ \: \: \: = 1 \times {10}^{ - 6} {m}^{2} }$

$\bold{\: Pressure \: on \: nail \: A \: = \: \frac{force}{area} } \\ \bold{ \: \: \: \: \: \: \: \: \: = \frac{1.5}{2 \times 1 \times {10}^{ - 6} } } \\ \bold{ \: \: \: = \frac{ \cancel{1.5} \: \: ³}{2 \times 1 \times {10}^{ - 6} \times \cancel{10} \: \: ²} } \\ \\ \bold{ \: \: \: = \: 7.5 \times {10}^{5}Pa \: \: \: ...ans}$

$\bold{Pressure \: on \: nail \: B \: = \frac{force}{area} } \\ \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \: \frac{1.5}{6 \times 1 \times {10}^{ - 6} } } \\ \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \: \frac { \cancel{1.5} \: \: ³}{ \cancel6 \:² \times 1 \times {10}^{ - 6} \times \cancel{10}\: ² } } \\ \bold{ = \: 2.5 \times {10}^{5}Pa \: \: \: ....ans}$

hope it helps you...

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