Question

a Hammer exerts a force of 1.5 Newton on each of the two Nails A and B .the area of cross section of tip of the nail is 2 mm square while that of Naill b is 6 mm square calculate pressure on each nail in Pascal.

Answer 1

use formula ,

$pressure \: = \frac{force}{area}$
change all quantities in SI unit...
i.e.
$1 {mm}^{2} = {10}^{ - 6} {m}^{2}$

Pressure on nail-A:

= (force on A) / (Cross section Area of tip of A)
= 1.5/(2x10^(-6))
= 7.5 x 10^5 Pa

Pressure on Nail-B:

= (force applied on B)/(CSA of tip of B)
= 1.5/(6x10^(-6))
= 2.5 x 10^5 Pa


Hope , it helped..

Answer 2

F=1.5 N

Mass of A=2 mm²=0.000002 m²

Mass of B=6 mm²=0.000006 m²

Pressure on A=Force/Area of A=1.5/0.000002=7,50,000 Pa=7.5×10^5 Pa

Pressure on B=Force/Area of B=1.5/0.000006=2,50,000 Pa=2.5×10^5 Pa

I hope it help you....

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