a hammer exerts a force of 1.5N on each of the two nails A and B .the area of cross section of tip nail A is 2mm² while that of nail B is 6mm² calculate pressure on each nail in pascal
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on A,
force = 1.5 N
area = 2 mm^2
1 mm = 1/1000 m = 0.001m
1 mm^2 = 1 mm*1mm = 0.001 m * 0.001 m = 0.000001 m^2 = 10^-6 m^2
P = 1.5N/ (2*10^-6) m^2 = 7.5*10^5 Pa
on B,
P = 1.5N/(6*10^-6) m^2 = 2.5*10^5 Pa
force = 1.5 N
area = 2 mm^2
1 mm = 1/1000 m = 0.001m
1 mm^2 = 1 mm*1mm = 0.001 m * 0.001 m = 0.000001 m^2 = 10^-6 m^2
P = 1.5N/ (2*10^-6) m^2 = 7.5*10^5 Pa
on B,
P = 1.5N/(6*10^-6) m^2 = 2.5*10^5 Pa
Anonymous:
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thank u sooooooooooo much
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hey,do u know any short cut for calculating 1.5 N / (2*10^-6) m^2
u did it fast
how did u do it ?
please tell i have exam tommorow
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