Question

a hammer has a head of mass 4kg and is used to drive the nail into wooden block the workman merely allows the hammer to dropped from a height of 60cm if it pierce 0.6 cm at each blow find average retarding force​

Answer 1

Answer:

Since a force of F is required to penetrate the wall, a force F is applied of the nail. To move the nail by x in a direction opposite the Force, the energy needed is F X x

So Kinetic energy of the hammer will be lost as work done by force.

0.5 mv^2=Fx

V=√(2Fx/m)

Answer 2

The average retarding force will be 400 N.

Given,

Mass(M) of the hammer = 4 kg

Height(H) from where it drops = 60 cm

Penetration(h) of the nail = 0.6 cm.

To find,

the average retarding force.

Solution:

Conservation of energy is need to be used here, as the hammer starts from rest and comes to rest so the net work done is zero.

60 cm = 60/100 m

= 0.6 m

0.6 cm = 0.6/100 m

= 0.06 m

MgH - mgh = 0

MgH = mgh (F = mg)

4 x 10 x 0.6 = F x 0.06 (g = 10 m/s^2)

24 = F x 0.06

F = 24/0.06

F = 400 N.

The average retarding force will be 400 N.

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