Question

A hammer having a mass of 1 kg going with a speed of 6 m/s hits a wall and comes to rest in 0. 1 sec. Compute the obstacle force that makes the hammer stop?

Answer 1

Explanation:

Mass of the hammer=1kg

Initial velocity(u)=6ms1

Final velocity(v)=0ms1

Tie taken(t)=0.1sec

(i)

impluse=m(v−u)=1×(0−6)

=>−6ms1

(ii)

a retarding force that stops a hammer

i.e.,

$f \: = \frac{impulse \: }{time} = \frac{ - 6}{0.1}$

$= > 60 \: n \:$

iii)

retarding of the hammer

$a \: = \frac{f}{m} = \frac{60}{1} = \: 60 \: ms \: - 2$