Question

A hammer of 1 kg moving with a speed 100m/s strikes at nail.the nail stops the hammer in a very short time. What is the force of the nail on the hammer?​

Answer 1

Given

Mass of hammer = 1 kg

Initial Velocity = 100 m/s

Final velocity = 0 m/s

Since stops finally

Time = 0.02 s

To find

Force of the nail on the hammer

Solution -

Force is defined as product of mass and acceleration

$\bigstar\ \; \bf F=ma$

Acceleration is defined as rate of change in velocity

$\bf \bigstar\ \; a=\dfrac{v-u}{t}$

So , Final formula for force is ,

$\bigstar\ \; \bf F=m(\dfrac{v-u}{t}$

$\begin{gathered}\to \rm F=(1) (\dfrac{0-100}{0.02}) \\\\\to \rm F=\dfrac{-100}{\frac{2}{100}}\\\\\to \rm F=\dfrac{-10000}{2}\\\\\to \rm F=-5000\ N\ \; \red{\bigstar}\end{gathered}$

So , force of the nail on the hammer is - 5000 N

Note : - Ve sign denotes force on hammer due to nail.

Answer 2

Answer:

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