a hammer of 2.5 kg moving with a speed of 1 metre per second strikes the head of a nail driving it 10 centimetre into the wall. find the acceleration on the hammer and impulse provided to it
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v2 = u2 + 2as
10 cm = 0.1 m
02 = 12 + 2*a * 0.1
- 1 = 0.2 * a
-1 / 0.2 = a
a = - 5 m / s2
Impulse = Change in momentum
= m(v - u)
= 2.5 kg ( 0 - 1)
= - 2.5 kg m /s
Acceleration : - 5 m /. s2
Impulse = - 2.5 kg m / s
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10 cm = 0.1 m
02 = 12 + 2*a * 0.1
- 1 = 0.2 * a
-1 / 0.2 = a
a = - 5 m / s2
Impulse = Change in momentum
= m(v - u)
= 2.5 kg ( 0 - 1)
= - 2.5 kg m /s
Acceleration : - 5 m /. s2
Impulse = - 2.5 kg m / s
plz mark as brainiest
avisha38:
i am from kolkata
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