Question

A hammer of 450 gram. Moves at 590 m/s strikes a nail. The nail stops the hammer in a very short time of 0.1s. What is force of nail on the hammer​

Answer 1

Given:

• Mass of hammer =m = 450 gram = 0.45 kg
• Initial speed= u = 590m/s
• Final Speed= v = 0m/s
• Time = t = 0.1s

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Need to find:

• Force of nail on the hammer =?

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Solution:

We know, from the 1st equation of motion, that,

$v = u + at$

substitute the values

$\implies 0 = 590 + a \times 0.1$

$\implies \: a \times 0.1= - 590$

$\purple{\bold{\boxed{\implies a = - 5900 \: m {s}^{2}}}}$

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We know from NLM that,

Force= Mass × Acceleration

• Given Mass= 0.45kg
• And we got Acceleration = 5900 m/${s}^{2}$

Substitute the values!

$\implies Force = 0.45kg \times (-5900) m/ {s}^{2}$

$\large{\red{\bold{\boxed{\implies Force = -2655N}}}}$

▪Here minus (-)sign indicates that the Force acts in the direction opposite to the motion of hammer.